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For the balanced equation shown below, if the reaction of 1,567 grams of C4H8O and 5,792 grams of O2 produces a 61.5% yield, how many grams of CO2 would be produced?
2C4H8O+11O2=>8CO2+8H2O
1567 / 72 = 21.764 (11) = 239.403
5792 / 32 = 181 (2) = 362
C4H8O is the limiting reagent.
2 : 8
21.764 (4) = 87.056 mol * 44 = 3830.464 * 0.615 = 2355.73536 grams
For the balanced equation shown below, if the reaction of 1,567 grams of C4H8O and 5,792 grams of O2 produces a 61.5% yield, how many grams of CO2 would be produced?
2C4H8O+11O2=>8CO2+8H2O
1567 / 72 = 21.764 (11) = 239.403
5792 / 32 = 181 (2) = 362
C4H8O is the limiting reagent.
2 : 8
21.764 (4) = 87.056 mol * 44 = 3830.464 * 0.615 = 2355.73536 grams