Here's a calculator to see why you were wrong:
Sorry, you're wrong! Better luck next time! The answer was: C4H8O
For the balanced equation shown below, what would be the limiting reagent if 39.8 grams of C4H8O were reacted with 143 grams of O2?
2C4H8O+11O2=>8CO2+8H2O
39.8/72 = 0.6mol
143/32 = 4.5mol
C4H8O is the limiting reagent.
For the balanced equation shown below, what would be the limiting reagent if 39.8 grams of C4H8O were reacted with 143 grams of O2?
2C4H8O+11O2=>8CO2+8H2O
39.8/72 = 0.6mol
143/32 = 4.5mol
C4H8O is the limiting reagent.