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For the balanced equation shown below, if 38.2 grams of C2H7N were reacted with 65.0 grams of O2, how many grams of H2O would be produced?
4C2H7N+17O2=>8CO2+14H2O+4NO
38.2/45 = 0.8488888888888889 mol (17) = 14.43111111111111 mol
65/32 = 2.03125 mol (4) = 8.125 mol
O2 is the limiting reagent.
17 : 14
32 (17) = 544
18 (14) = 252
252 / 544 = 0.4632352941176471 (65) = 30.11029411764706g
For the balanced equation shown below, if 38.2 grams of C2H7N were reacted with 65.0 grams of O2, how many grams of H2O would be produced?
4C2H7N+17O2=>8CO2+14H2O+4NO
38.2/45 = 0.8488888888888889 mol (17) = 14.43111111111111 mol
65/32 = 2.03125 mol (4) = 8.125 mol
O2 is the limiting reagent.
17 : 14
32 (17) = 544
18 (14) = 252
252 / 544 = 0.4632352941176471 (65) = 30.11029411764706g