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For the balanced equation shown below, what would be the limiting reagent if 78.4 grams of C4H8O were reacted with 151 grams of O2?
2C4H8O+11O2=>8CO2+8H2O
78.4/72 = 1mol
151/32 = 4.7mol
O2 is the limiting reagent.
For the balanced equation shown below, what would be the limiting reagent if 78.4 grams of C4H8O were reacted with 151 grams of O2?
2C4H8O+11O2=>8CO2+8H2O
78.4/72 = 1mol
151/32 = 4.7mol
O2 is the limiting reagent.