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For the balanced equation shown below, if 10.2 grams of CH4 were reacted with 96.5 grams of Cl2, how many grams of HCl would be produced?
CH4+4Cl2=>4HCl+CCl4
10.2/16 = 0.6375 mol (4) = 2.55 mol
96.5/71 = 1.359154929577465 mol
Cl2 is the limiting reagent.
4 : 4 = 1 : 1
1.359154929577465 (36.5) = 49.60915492957746g
For the balanced equation shown below, if 10.2 grams of CH4 were reacted with 96.5 grams of Cl2, how many grams of HCl would be produced?
CH4+4Cl2=>4HCl+CCl4
10.2/16 = 0.6375 mol (4) = 2.55 mol
96.5/71 = 1.359154929577465 mol
Cl2 is the limiting reagent.
4 : 4 = 1 : 1
1.359154929577465 (36.5) = 49.60915492957746g