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For the balanced equation shown below, what would be the limiting reagent if 14.9 grams of C2H3O2Cl were reacted with 2.57 grams of O2?
4C2H3O2Cl+3O2=>8CO+6H2O+2Cl2
14.9/94.5 = 0.157mol
2.57/32 = 0.08mol
O2 is the limiting reagent.
For the balanced equation shown below, what would be the limiting reagent if 14.9 grams of C2H3O2Cl were reacted with 2.57 grams of O2?
4C2H3O2Cl+3O2=>8CO+6H2O+2Cl2
14.9/94.5 = 0.157mol
2.57/32 = 0.08mol
O2 is the limiting reagent.