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Sorry, you're wrong! Better luck next time! The answer was: O2
For the balanced equation shown below, what would be the limiting reagent if 17.6 grams of C2H5N were reacted with 44.3 grams of O2?
4C2H5N+17O2=>8CO2+10H2O+4NO2
17.6/43 = 0.4mol
44.3/32 = 1.4mol
O2 is the limiting reagent.
For the balanced equation shown below, what would be the limiting reagent if 17.6 grams of C2H5N were reacted with 44.3 grams of O2?
4C2H5N+17O2=>8CO2+10H2O+4NO2
17.6/43 = 0.4mol
44.3/32 = 1.4mol
O2 is the limiting reagent.