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Sorry, you're wrong! Better luck next time! The answer was: O2
For the balanced equation shown below, what would be the limiting reagent if 69.6 grams of NH3 were reacted with 127 grams of O2?
4NH3+5O2=>4NO+6H2O
69.6/17 = 4.09mol
127/32 = 3.96mol
O2 is the limiting reagent.
For the balanced equation shown below, what would be the limiting reagent if 69.6 grams of NH3 were reacted with 127 grams of O2?
4NH3+5O2=>4NO+6H2O
69.6/17 = 4.09mol
127/32 = 3.96mol
O2 is the limiting reagent.