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For the balanced equation shown below, if 53.0 grams of CH2F2 were reacted with 83.7 grams of O2, how many grams of CO2 would be produced?
2CH2F2+3O2=>2CO2+2H2O+2F2
53/52 = 1.019230769230769 mol (3) = 3.057692307692308 mol
83.7/32 = 2.615625 mol (2) = 5.23125 mol
CH2F2 is the limiting reagent.
2 : 2
1.019230769230769 (44) = 44.84615384615384g
For the balanced equation shown below, if 53.0 grams of CH2F2 were reacted with 83.7 grams of O2, how many grams of CO2 would be produced?
2CH2F2+3O2=>2CO2+2H2O+2F2
53/52 = 1.019230769230769 mol (3) = 3.057692307692308 mol
83.7/32 = 2.615625 mol (2) = 5.23125 mol
CH2F2 is the limiting reagent.
2 : 2
1.019230769230769 (44) = 44.84615384615384g