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For the balanced equation shown below, what would be the limiting reagent if 50.9 grams of C2H3Cl3 were reacted with 26.1 grams of O2?
4C2H3Cl3+11O2=>8CO2+6H2O+6Cl2
50.9/133.5 = 0.4mol
26.1/32 = 0.8mol
O2 is the limiting reagent.
For the balanced equation shown below, what would be the limiting reagent if 50.9 grams of C2H3Cl3 were reacted with 26.1 grams of O2?
4C2H3Cl3+11O2=>8CO2+6H2O+6Cl2
50.9/133.5 = 0.4mol
26.1/32 = 0.8mol
O2 is the limiting reagent.