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Sorry, you're wrong! Better luck next time! The answer was: 18.4 grams
For the balanced equation shown below, if 25.8 grams of C2H3F3 were reacted with 16.0 grams of O2, how many grams of HF would be produced?
C2H3F3+O2=>2CO+3HF
25.8/84 = 0.3071428571428571 mol
16/32 = 0.5 mol
C2H3F3 is the limiting reagent.
1 : 3
0.3071428571428571 (3) = 0.9214285714285713 mol
0.9214285714285713 (20) = 18.42857142857143g
For the balanced equation shown below, if 25.8 grams of C2H3F3 were reacted with 16.0 grams of O2, how many grams of HF would be produced?
C2H3F3+O2=>2CO+3HF
25.8/84 = 0.3071428571428571 mol
16/32 = 0.5 mol
C2H3F3 is the limiting reagent.
1 : 3
0.3071428571428571 (3) = 0.9214285714285713 mol
0.9214285714285713 (20) = 18.42857142857143g