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Sorry, you're wrong! Better luck next time! The answer was: C2H3N
For the balanced equation shown below, what would be the limiting reagent if 34.8 grams of C2H3N were reacted with 107 grams of O2?
4C2H3N+9O2=>8CO+6H2O+4NO
34.8/41 = 0.848mol
107/32 = 3.34 mol
C2H3N is the limiting reagent.
For the balanced equation shown below, what would be the limiting reagent if 34.8 grams of C2H3N were reacted with 107 grams of O2?
4C2H3N+9O2=>8CO+6H2O+4NO
34.8/41 = 0.848mol
107/32 = 3.34 mol
C2H3N is the limiting reagent.